deduction guides for std::map
Defined in header <map>
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template< class InputIt, class Comp = std::less<iter_key_t<InputIt>>, |
(1) | (since C++17) |
template< class Key, class T, |
(2) | (since C++17) |
template< class InputIt, class Alloc > map( InputIt, InputIt, Alloc ) |
(3) | (since C++17) |
template< class Key, class T, class Allocator > map( std::initializer_list<std::pair<Key, T>>, Allocator ) |
(4) | (since C++17) |
where the type aliases iter_key_t
, iter_val_t
, iter_to_alloc_t
are defined as if as follows
template< class InputIt > using iter_key_t = std::remove_const_t< |
(exposition only) | |
template< class InputIt > using iter_val_t = typename std::iterator_traits<InputIt>::value_type::second_type; |
(exposition only) | |
template< class InputIt > using iter_to_alloc_t = std::pair< |
(exposition only) | |
This deduction guide is provided for map to allow deduction from an iterator range (overloads (1,3)) and std::initializer_list (overloads (2,4)). These overloads participate in overload resolution only if InputIt
satisfies LegacyInputIterator, Alloc
satisfies Allocator, and Comp
does not satisfy Allocator.
Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type
must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.
Example
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3025 | C++17 | initializer-list guides take std::pair<const Key, T> | use std::pair<Key, T> |