deduction guides for std::queue

 

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std::queue

Member functions

queue::queue

queue::~queue

queue::operator=

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queue::front

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Capacity

queue::empty

queue::size

Modifiers

queue::push

queue::emplace (C++11)

queue::pop

queue::swap (C++11)

Non-member functions

operator==operator!=operator<operator>operator<=operator>=operator<=> (C++20)

std::swap

Deduction guides(C++17)

 

Defined in header <queue>
template< class Container > queue( Container )   -> queue<typename Container::value_type, Container>;	(1)	(since C++17)
template< class InputIt > queue( InputIt, InputIt )   -> queue<typename std::iterator_traits<InputIt>::value_type>;	(2)	(since C++23)
template< class Container, class Alloc > queue( Container, Alloc )   -> queue<typename Container::value_type, Container>;	(3)	(since C++17)
template< class InputIt, class Alloc > queue( InputIt, InputIt, Alloc )   -> queue<typename std::iterator_traits<InputIt>::value_type,     std::deque<typename std::iterator_traits<InputIt>::value_type, Alloc>>;	(4)	(since C++23)

These deduction guides are provided for queue to allow deduction from underlying container type.

1) Deduces underlying container type from the argument.

2) Deduces the element type from the iterator, using std::deque<typename std::iterator_traits<InputIt>::value_type> as the underlying container type.

3-4) Same as (1-2), except that the allocator is provided.

These overloads participate in overload resolution only if

• InputIt (if exists) satisfies LegacyInputIterator,
• Container (if exists) does not satisfy Allocator,
• for (3) (until C++23)(4) (since C++23), Alloc satisfies Allocator, and
• std::uses_allocator_v<Container, Alloc> is true if both Container and Alloc exist.

Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.

Example

Run this code

#include <vector>
#include <queue>
int main() {
   std::vector<int> v = {1,2,3,4};
   std::queue s{v};    // guide #1 deduces std::queue<int, vector<int>>
}