std::vector<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
(until C++20) | |
constexpr void pop_back(); |
(since C++20) | |
Removes the last element of the container.
Calling pop_back
on an empty container results in undefined behavior.
Iterators and references to the last element, as well as the end() iterator, are invalidated.
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
Throws nothing.
Example
Run this code
#include <vector> #include <iostream> template<typename T> void print(T const & xs) { std::cout << "[ "; for(auto const & x : xs) { std::cout << x << ' '; } std::cout << "]\n"; } int main() { std::vector<int> numbers; print(numbers); numbers.push_back(5); numbers.push_back(3); numbers.push_back(4); print(numbers); numbers.pop_back(); print(numbers); }
Output:
[ ] [ 5 3 4 ] [ 5 3 ]
See also
adds an element to the end (public member function) |