std::accumulate
Defined in header <numeric>
|
||
(1) | ||
template< class InputIt, class T > T accumulate( InputIt first, InputIt last, T init ); |
(until C++20) | |
template< class InputIt, class T > constexpr T accumulate( InputIt first, InputIt last, T init ); |
(since C++20) | |
(2) | ||
template< class InputIt, class T, class BinaryOperation > T accumulate( InputIt first, InputIt last, T init, |
(until C++20) | |
template< class InputIt, class T, class BinaryOperation > constexpr T accumulate( InputIt first, InputIt last, T init, |
(since C++20) | |
Computes the sum of the given value init
and the elements in the range [first, last)
. The first version uses operator+
to sum up the elements, the second version uses the given binary function op
, both applying std::move to their operands on the left hand side (since C++20).
|
(until C++11) |
|
(since C++11) |
Parameters
first, last | - | the range of elements to sum |
init | - | initial value of the sum |
op | - | binary operation function object that will be applied. The binary operator takes the current accumulation value a (initialized to init ) and the value of the current element b . The signature of the function should be equivalent to the following: Ret fun(const Type1 &a, const Type2 &b); The signature does not need to have const &. |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator.
| ||
-T must meet the requirements of CopyAssignable and CopyConstructible.
|
Return value
Notes
std::accumulate
performs a left fold. In order to perform a right fold, one must reverse the order of the arguments to the binary operator, and use reverse iterators.
Common mistakes
If left to type inference, op
operates on values of the same type as init
which can result in unwanted casting of the iterator elements. For example, std::accumulate(v.begin(), v.end(), 0) likely does not give the result one wishes for when v
is std::vector<double>.
Possible implementation
First version |
---|
template<class InputIt, class T> constexpr // since C++20 T accumulate(InputIt first, InputIt last, T init) { for (; first != last; ++first) { init = std::move(init) + *first; // std::move since C++20 } return init; } |
Second version |
template<class InputIt, class T, class BinaryOperation> constexpr // since C++20 T accumulate(InputIt first, InputIt last, T init, BinaryOperation op) { for (; first != last; ++first) { init = op(std::move(init), *first); // std::move since C++20 } return init; } |
Example
#include <iostream> #include <vector> #include <numeric> #include <string> #include <functional> int main() { std::vector<int> v{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; int sum = std::accumulate(v.begin(), v.end(), 0); int product = std::accumulate(v.begin(), v.end(), 1, std::multiplies<int>()); auto dash_fold = [](std::string a, int b) { return std::move(a) + '-' + std::to_string(b); }; std::string s = std::accumulate(std::next(v.begin()), v.end(), std::to_string(v[0]), // start with first element dash_fold); // Right fold using reverse iterators std::string rs = std::accumulate(std::next(v.rbegin()), v.rend(), std::to_string(v.back()), // start with last element dash_fold); std::cout << "sum: " << sum << '\n' << "product: " << product << '\n' << "dash-separated string: " << s << '\n' << "dash-separated string (right-folded): " << rs << '\n'; }
Output:
sum: 55 product: 3628800 dash-separated string: 1-2-3-4-5-6-7-8-9-10 dash-separated string (right-folded): 10-9-8-7-6-5-4-3-2-1
See also
computes the differences between adjacent elements in a range (function template) | |
computes the inner product of two ranges of elements (function template) | |
computes the partial sum of a range of elements (function template) | |
(C++17) |
similar to std::accumulate, except out of order (function template) |