std::ranges::copy, std::ranges::copy_if, std::ranges::copy_result, std::ranges::copy_if_result
Defined in header <algorithm>
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Call signature |
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template< std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O > requires std::indirectly_copyable<I, O> |
(1) | (since C++20) |
template< ranges::input_range R, std::weakly_incrementable O > requires std::indirectly_copyable<ranges::iterator_t<R>, O> |
(2) | (since C++20) |
template< std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O, class Proj = std::identity, |
(3) | (since C++20) |
template< ranges::input_range R, std::weakly_incrementable O, class Proj = std::identity, |
(4) | (since C++20) |
Helper types |
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template< class I, class O > using copy_result = ranges::in_out_result<I, O>; |
(5) | (since C++20) |
template< class I, class O > using copy_if_result = ranges::in_out_result<I, O>; |
(6) | (since C++20) |
Copies the elements in the range, defined by [first, last)
, to another range beginning at result
.
[first, last)
starting from first and proceeding to last - 1. The behavior is undefined if result
is within the range [first, last)
. In this case, ranges::copy_backward may be used instead.pred
returns true. The relative order of the elements that are copied is preserved. The behavior is undefined if the source and the destination ranges overlap.r
as the source range, as if using ranges::begin(r) as first
and ranges::end(r) as last
.The function-like entities described on this page are niebloids, that is:
- Explicit template argument lists may not be specified when calling any of them.
- None of them is visible to argument-dependent lookup.
- When one of them is found by normal unqualified lookup for the name to the left of the function-call operator, it inhibits argument-dependent lookup.
In practice, they may be implemented as function objects, or with special compiler extensions.
Parameters
first, last | - | the range of elements to copy |
r | - | the range of elements to copy |
result | - | the beginning of the destination range. |
pred | - | predicate to apply to the projected elements |
proj | - | projection to apply to the elements |
Return value
A ranges::in_out_result containing an input iterator equal to last
and an output iterator past the last element copied.
Complexity
Notes
In practice, implementations of std::ranges::copy
avoid multiple assignments and use bulk copy functions such as std::memmove if the value type is TriviallyCopyable and the iterator types satisfy contiguous_iterator
.
When copying overlapping ranges, std::ranges::copy
is appropriate when copying to the left (beginning of the destination range is outside the source range) while std::ranges::copy_backward is appropriate when copying to the right (end of the destination range is outside the source range).
Possible implementation
First version |
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struct copy_fn { template< std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O > requires std::indirectly_copyable<I, O> constexpr ranges::copy_result<I, O> operator()( I first, S last, O result ) const { for (; first != last; ++first, (void)++result) { *result = *first; } return {std::move(first), std::move(result)}; } template< ranges::input_range R, std::weakly_incrementable O > requires std::indirectly_copyable<ranges::iterator_t<R>, O> constexpr ranges::copy_result<ranges::borrowed_iterator_t<R>, O> operator()( R&& r, O result ) const { return (*this)(ranges::begin(r), ranges::end(r), std::move(result)); } }; inline constexpr copy_fn copy; |
Second version |
struct copy_if_fn { template< std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O, class Proj = std::identity, std::indirect_unary_predicate<std::projected<I, Proj>> Pred > requires std::indirectly_copyable<I, O> constexpr ranges::copy_if_result<I, O> operator()( I first, S last, O result, Pred pred, Proj proj = {} ) const { for (; first != last; ++first) { if (std::invoke(pred, std::invoke(proj, *first))) { *result = *first; ++result; } } return {std::move(first), std::move(result)}; } template< ranges::input_range R, std::weakly_incrementable O, class Proj = std::identity, std::indirect_unary_predicate< std::projected<ranges::iterator_t<R>, Proj>> Pred > requires std::indirectly_copyable<ranges::iterator_t<R>, O> constexpr ranges::copy_if_result<ranges::borrowed_iterator_t<R>, O> operator()( R&& r, O result, Pred pred, Proj proj = {} ) const { return (*this)(ranges::begin(r), ranges::end(r), std::move(result), std::ref(pred), std::ref(proj)); } }; inline constexpr copy_if_fn copy_if; |
Example
The following code uses copy
to both copy the contents of one vector
to another and to display the resulting vector
:
#include <algorithm> #include <iostream> #include <vector> #include <iterator> #include <numeric> int main() { std::vector<int> from_vector(10); std::iota(from_vector.begin(), from_vector.end(), 0); std::vector<int> to_vector; namespace ranges = std::ranges; ranges::copy(from_vector.begin(), from_vector.end(), std::back_inserter(to_vector)); // or, alternatively, // std::vector<int> to_vector(from_vector.size()); // ranges::copy(from_vector.begin(), from_vector.end(), to_vector.begin()); // either way is equivalent to // std::vector<int> to_vector = from_vector; std::cout << "to_vector contains: "; ranges::copy(to_vector, std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; std::cout << "odd numbers in to_vector are: "; ranges::copy_if(to_vector, std::ostream_iterator<int>(std::cout, " "), [](int x) { return (x % 2) == 1; }); std::cout << '\n'; }
Output:
to_vector contains: 0 1 2 3 4 5 6 7 8 9 odd numbers in to_vector are: 1 3 5 7 9
See also
(C++20) |
copies a range of elements in backwards order (niebloid) |
(C++20) |
creates a copy of a range that is reversed (niebloid) |
(C++20) |
copies a number of elements to a new location (niebloid) |
(C++20) |
assigns a range of elements a certain value (niebloid) |
(C++20)(C++20) |
copies a range of elements omitting those that satisfy specific criteria (niebloid) |
(C++11) |
copies a range of elements to a new location (function template) |