std::ranges::fill
From cppreference.com
Defined in header <algorithm>
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Call signature |
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template< class T, std::output_iterator<const T&> O, std::sentinel_for<O> S > constexpr O fill( O first, S last, const T& value ); |
(1) | (since C++20) |
template< class T, ranges::output_range<const T&> R > constexpr ranges::borrowed_iterator_t<R> fill( R&& r, const T& value ); |
(2) | (since C++20) |
1) Assigns the given
value
to the elements in the range [first, last)
.2) Same as (1), but uses
r
as the source range, as if using ranges::begin(r) as first
and ranges::end(r) as last
.The function-like entities described on this page are niebloids, that is:
- Explicit template argument lists may not be specified when calling any of them.
- None of them is visible to argument-dependent lookup.
- When one of them is found by normal unqualified lookup for the name to the left of the function-call operator, it inhibits argument-dependent lookup.
In practice, they may be implemented as function objects, or with special compiler extensions.
Parameters
first, last | - | the range of elements to modify |
r | - | the range of elements to modify |
value | - | the value to be assigned |
Return value
An output iterator that compares equal to last
.
Complexity
Exactly last - first
assignments.
Possible implementation
struct fill_fn { template< class T, std::output_iterator<const T&> O, std::sentinel_for<O> S > constexpr O operator()( O first, S last, const T& value ) const { while (first != last) { *first++ = value; } return first; } template< class T, ranges::output_range<const T&> R > constexpr ranges::borrowed_iterator_t<R> operator()( R&& r, const T& value ) const { return (*this)(ranges::begin(r), ranges::end(r), value); } }; inline constexpr fill_fn fill; |
Example
The following code uses ranges::fill()
to set all of the elements of a vector
of int
s first to -1, then to 10.
Run this code
#include <algorithm> #include <vector> #include <iostream> int main() { std::vector<int> v{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; namespace ranges = std::ranges; ranges::fill(v.begin(), v.end(), -1); for (auto elem : v) { std::cout << elem << " "; } std::cout << "\n"; ranges::fill(v, 10); for (auto elem : v) { std::cout << elem << " "; } std::cout << "\n"; }
Output:
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 10 10 10 10 10 10 10 10 10 10
See also
(C++20) |
assigns a value to a number of elements (niebloid) |
(C++20)(C++20) |
copies a range of elements to a new location (niebloid) |
(C++20) |
saves the result of a function in a range (niebloid) |
(C++20) |
applies a function to a range of elements (niebloid) |
copy-assigns the given value to every element in a range (function template) |