std::experimental::filesystem::path::compare
From cppreference.com
< cpp | experimental | fs | path
| int compare( const path& p ) const noexcept; |
(1) | (filesystem TS) |
| int compare( const string_type& str ) const; |
(2) | (filesystem TS) |
| int compare( const value_type* s ) const; |
(3) | (filesystem TS) |
Compares the lexical representations of the path and another path.
1) Returns a value less than, equal to or greater than 0 if the native representation of the path (native()) is respectively lexicographically less than, equal to or greater than the native representation of
p (p.native()). Comparison is performed element-wise, as if by iterating both paths from begin() to end().2) Equivalent to compare(path(str)).
3) Equivalent to compare(path(s)).
Parameters
| p | - | a path to compare to |
| str | - | a string representing path to compare to |
| s | - | a null-terminated string representing path to compare to |
Return value
A value less than 0 if the path is lexicographically less than the given path.
A value equal to 0 if the path is lexicographically equal to the given path.
A value greater than 0 if the path is lexicographically greater than the given path.
Exceptions
2-3) May throw implementation-defined exceptions.
Notes
For two-way comparisons, binary operators may be more suitable.
Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; void demo(int rc, fs::path p1, fs::path p2) { if(rc < 0) std::cout << p1 << " < " << p2 << '\n'; else if(rc > 0) std::cout << p1 << " > " << p2 << '\n'; else if(rc == 0) std::cout << p1 << "==" << p2 << '\n'; } int main() { fs::path p1 = "/a/b/"; // as if "a/b/." for lexicographical iteration fs::path p2 = "/a/b/#"; demo(p1.compare(p2), p1, p2); demo(p1.compare("a/b/_"), p1, "a/b/_"); }
Output:
"/a/b/" > "/a/b/#" "/a/b/" < "a/b/_"
See also
| lexicographically compares two paths (function) |