std::experimental::filesystem::path::root_directory
From cppreference.com
< cpp | experimental | fs | path
path root_directory() const; |
(filesystem TS) | |
Returns the root directory of the path. If the path does not include root name, returns path().
Parameters
(none)
Return value
The root directory of the path.
Exceptions
May throw implementation-defined exceptions.
Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { fs::path p = fs::current_path(); std::cout << "The current path " << p << " decomposes into:\n" << "root name " << p.root_name() << '\n' << "root directory " << p.root_directory() << '\n' << "relative path " << p.relative_path() << '\n'; }
Possible output:
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into: root name "C:" root directory "\" relative path "Users\abcdef\Local Settings\temp"
See also
returns the root-name of the path, if present (public member function) | |
returns the root path of the path, if present (public member function) |