std::chrono::year_month_weekday::operator+=, std::chrono::year_month_weekday::operator-=
From cppreference.com
< cpp | chrono | year month weekday
constexpr std::chrono::year_month_weekday& operator+=( const std::chrono::years& dy ) const noexcept; |
(1) | (since C++20) |
constexpr std::chrono::year_month_weekday& operator+=( const std::chrono::months& dm ) const noexcept; |
(2) | (since C++20) |
constexpr std::chrono::year_month_weekday& operator-=( const std::chrono::years& dy ) const noexcept; |
(3) | (since C++20) |
constexpr std::chrono::year_month_weekday& operator-=( const std::chrono::months& dm ) const noexcept; |
(4) | (since C++20) |
Modifies the time point *this represents by the duration dy
or dm
.
1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (1,3) are preferred if the call would otherwise be ambiguous.
Example
Run this code
#include <iostream> #include <chrono> int main() { std::cout << std::boolalpha; auto ymwi {1/std::chrono::Wednesday[2]/2021}; ymwi += std::chrono::years(5); std::cout << (static_cast<std::chrono::year_month_day>(ymwi) == std::chrono::year(2026)/1/14) << ' '; ymwi -= std::chrono::months(1); std::cout << (static_cast<std::chrono::year_month_day>(ymwi) == std::chrono::day(10)/12/2025) << '\n'; }
Output:
true true
See also
(C++20) |
adds or subtracts a year_month_weekday and some number of years or months (function) |