std::list<T,Allocator>::pop_back
From cppreference.com
void pop_back(); |
||
Removes the last element of the container.
Calling pop_back
on an empty container results in undefined behavior.
References and iterators to the erased element are invalidated.
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
Throws nothing.
Example
Run this code
#include <list> #include <iostream> template<typename T> void print(T const & xs) { std::cout << "[ "; for(auto const & x : xs) { std::cout << x << ' '; } std::cout << "]\n"; } int main() { std::list<int> numbers; print(numbers); numbers.push_back(5); numbers.push_back(3); numbers.push_back(4); print(numbers); numbers.pop_back(); print(numbers); }
Output:
[ ] [ 5 3 4 ] [ 5 3 ]
See also
removes the first element (public member function) | |
adds an element to the end (public member function) |