std::list<T,Allocator>::swap
From cppreference.com
void swap( list& other ); |
(until C++17) | |
void swap( list& other ) noexcept(/* see below */); |
(since C++17) | |
Exchanges the contents of the container with those of other
. Does not invoke any move, copy, or swap operations on individual elements.
All iterators and references remain valid. It is unspecified whether an iterator holding the past-the-end value in this container will refer to this or the other container after the operation.
If std::allocator_traits<allocator_type>::propagate_on_container_swap::value is true, then the allocators are exchanged using an unqualified call to non-member |
(since C++11) |
Parameters
other | - | container to exchange the contents with |
Return value
(none)
Exceptions
(none) |
(until C++17) |
noexcept specification:
noexcept(std::allocator_traits<Allocator>::is_always_equal::value) |
(since C++17) |
Complexity
Constant.
Example
Run this code
#include <iostream> #include <list> template<class Os, class Co> Os& operator<<(Os& os, const Co& co) { os << "{"; for (auto const& i : co) { os << ' ' << i; } return os << " } "; } int main() { std::list<int> a1{1, 2, 3}, a2{4, 5}; auto it1 = std::next(a1.begin()); auto it2 = std::next(a2.begin()); int& ref1 = a1.front(); int& ref2 = a2.front(); std::cout << a1 << a2 << *it1 << ' ' << *it2 << ' ' << ref1 << ' ' << ref2 << '\n'; a1.swap(a2); std::cout << a1 << a2 << *it1 << ' ' << *it2 << ' ' << ref1 << ' ' << ref2 << '\n'; // Note that after swap the iterators and references stay associated with their // original elements, e.g. it1 that pointed to an element in 'a1' with value 2 // still points to the same element, though this element was moved into 'a2'. }
Output:
{ 1 2 3 } { 4 5 } 2 5 1 4 { 4 5 } { 1 2 3 } 2 5 1 4
See also
specializes the std::swap algorithm (function template) |