std::make_move_iterator
From cppreference.com
| Defined in header <iterator>
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| template< class Iter > std::move_iterator<Iter> make_move_iterator( Iter i ); |
(since C++11) (until C++17) |
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| template< class Iter > constexpr std::move_iterator<Iter> make_move_iterator( Iter i ); |
(since C++17) | |
make_move_iterator is a convenience function template that constructs a std::move_iterator for the given iterator i with the type deduced from the type of the argument.
Parameters
| i | - | input iterator to be converted to move iterator |
Return value
A std::move_iterator which can be used to move from the elements accessed through i
Possible implementation
template< class Iter > constexpr std::move_iterator<Iter> make_move_iterator( Iter i ) { return std::move_iterator<Iter>(std::move(i)); } |
Example
Run this code
#include <iostream> #include <iomanip> #include <list> #include <vector> #include <string> #include <iterator> auto print = [](auto const rem, auto const& seq) { for (std::cout << rem; auto const& str : seq) std::cout << std::quoted(str) << ' '; std::cout << '\n'; }; int main() { std::list<std::string> s{"one", "two", "three"}; std::vector<std::string> v1(s.begin(), s.end()); // copy std::vector<std::string> v2(std::make_move_iterator(s.begin()), std::make_move_iterator(s.end())); // move print("v1 now holds: ", v1); print("v2 now holds: ", v2); print("original list now holds: ", s); }
Possible output:
v1 now holds: "one" "two" "three" v2 now holds: "one" "two" "three" original list now holds: "" "" ""
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 2061 | C++11 | make_move_iterator did not convert array arguments to pointers
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made to convert |
See also
| (C++11) |
iterator adaptor which dereferences to an rvalue reference (class template) |
| (C++11) |
obtains an rvalue reference (function template) |