std::unique_ptr<T,Deleter>::release
From cppreference.com
< cpp | memory | unique ptr
pointer release() noexcept; |
(since C++11) (constexpr since C++23) |
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Releases the ownership of the managed object, if any.
get() returns nullptr after the call.
The caller is responsible for deleting the object.
Parameters
(none)
Return value
Pointer to the managed object or nullptr if there was no managed object, i.e. the value which would be returned by get() before the call.
Example
Run this code
#include <memory> #include <iostream> #include <cassert> struct Foo { Foo() { std::cout << "Foo\n"; } ~Foo() { std::cout << "~Foo\n"; } }; int main() { std::cout << "Creating new Foo...\n"; std::unique_ptr<Foo> up(new Foo()); std::cout << "About to release Foo...\n"; Foo* fp = up.release(); assert (up.get() == nullptr); assert (up == nullptr); std::cout << "Foo is no longer owned by unique_ptr...\n"; delete fp; }
Output:
Creating new Foo... Foo About to release Foo... Foo is no longer owned by unique_ptr... ~Foo
See also
returns a pointer to the managed object (public member function) | |
replaces the managed object (public member function) |