deduction guides for std::packaged_task
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< cpp | thread | packaged task
Defined in header <future>
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template<class R, class... Args> packaged_task(R(*)(Args...)) -> packaged_task<R(Args...)>; |
(1) | (since C++17) |
template<class F> packaged_task(F) -> packaged_task</*see below*/>; |
(2) | (since C++17) |
2) This overload participates in overload resolution only if &F::operator() is well-formed when treated as an unevaluated operand and decltype(&F::operator()) is of the form R(G::*)(A...) (optionally cv-qualified, optionally noexcept, optionally lvalue reference qualified) for some class type G. The deduced type is std::packaged_task<R(A...)>.
Example
Run this code
#include <future> int func(double) { return 0; } int main() { std::packaged_task f{func}; // deduces packaged_task<int(double)> int i = 5; std::packaged_task g = [&](double) { return i; }; // deduces packaged_task<int(double)> }