std::chrono::year::operator+=, std::chrono::year::operator-=
From cppreference.com
constexpr std::chrono::year& operator+=( const std::chrono::years& y ) noexcept; |
(1) | (since C++20) |
constexpr std::chrono::year& operator-=( const std::chrono::years& y ) noexcept; |
(2) | (since C++20) |
Adds or subtracts y.count() years from the year value.
1) Equivalent to *this = *this + y;
2) Equivalent to *this = *this - y;
Return value
A reference to this year
after modification.
Notes
If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
Example
Run this code
#include <iostream> #include <chrono> int main() { using namespace std::literals::chrono_literals; std::cout << std::boolalpha; std::chrono::year y {2020}; y += std::chrono::years(12); std::cout << (y == 2032y) << ' '; y -= std::chrono::years(33); std::cout << (y == 1999y) << '\n'; }
Output:
true true
See also
increments or decrements the year (public member function) | |
(C++20) |
performs arithmetic on year s (function) |