std::chrono::year::year

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< cpp‎ | chrono‎ | year
 
 
Utilities library
General utilities
Date and time
Function objects
Formatting library (C++20)
(C++11)
Relational operators (deprecated in C++20)
Integer comparison functions
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(C++20)
Swap and type operations
(C++14)
(C++11)
(C++11)
(C++11)
(C++17)
Common vocabulary types
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(C++17)
(C++17)
(C++17)
(C++11)
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(C++23)
Elementary string conversions
(C++17)
(C++17)
 
 
 
year() = default;
(1) (since C++20)
explicit constexpr year( int y ) noexcept;
(2) (since C++20)

Constructs a year object.

1) Default constructor leaves the year value uninitialized.
2) If y is in the range [-32767, 32767], constructs a year object holding the year value y. Otherwise the value held is unspecified.

Example

#include <chrono>
#include <iostream>
 
int main() {
    using namespace std::chrono;
 
    constexpr int leap_years = [] {
        int count{};
        for (int i{year::min()}; i <= int{year::max()}; ++i)
            if (year{i}.is_leap()) // uses constructor (2)
                ++count;
        return count;
    } ();
 
    static_assert(15891 == leap_years);
 
    std::cout << "There are " << leap_years << " leap years in the range ["
              << int(year::min()) << ", " << int(year::max()) << "].\n";
}

Output:

There are 15891 leap years in the range [-32767, 32767].