std::chrono::year_month_weekday_last::ok
From cppreference.com
< cpp | chrono | year month weekday last
constexpr bool ok() const noexcept; |
(since C++20) | |
Checks if this object represents a valid date. Since a year_month_weekday_last
represents the last weekday of a particular month, it is valid as long as the year, month and weekday are valid.
Return value
year().ok() && month().ok() && weekday().ok()
Example
Run this code
#include <iostream> #include <chrono> using namespace std::chrono; int main() { std::cout << std::boolalpha; auto ymwdl {Tuesday[last]/11/2020}; std::cout << (ymwdl.ok()) << ' '; ymwdl = Tuesday[last]/-2/2021; std::cout << (ymwdl.ok()) << ' '; ymwdl += months(0); // Normalize month std::cout << (ymwdl.ok()) << '\n'; }
Output:
true false true