std::chrono::year_month_weekday_last::operator sys_days, std::chrono::year_month_weekday_last::operator local_days
From cppreference.com
< cpp | chrono | year month weekday last
constexpr operator std::chrono::sys_days() const noexcept; |
(1) | (since C++20) |
explicit constexpr operator std::chrono::local_days() const noexcept; |
(2) | (since C++20) |
Converts *this
to a std::chrono::time_point representing the same date as this year_month_weekday_last
.
1) If ok() is true, returns a
sys_days
that represents the last weekday() of the year() and month(). Otherwise, the returned value is unspecified.2) Same as (1), but returns
local_days
instead of sys_days
. Equivalent to local_days(sys_days(*this).time_since_epoch()).Example
Run this code
#include <iostream> #include <chrono> using namespace std::chrono; int main() { std::cout << std::boolalpha; constexpr auto ymwdl {Tuesday[last]/11/2021}; static_assert(static_cast<local_days>(ymwdl) == static_cast<local_days>(November/30/2021)); // convert from field-based to serial-based to add days constexpr auto sd = static_cast<sys_days>(ymwdl); constexpr year_month_day ymd {sd + days(10)}; std::cout << (ymd == December/10/2021) << '\n'; }
Output:
true