std::reverse_iterator<Iter>::operator=
From cppreference.com
< cpp | iterator | reverse iterator
template< class U > reverse_iterator& operator=( const reverse_iterator<U>& other ); |
(until C++17) | |
template< class U > constexpr reverse_iterator& operator=( const reverse_iterator<U>& other ); |
(since C++17) | |
The underlying iterator is assigned the value of the underlying iterator of other
, i.e. other.base()
.
This overload participates in overload resolution only if |
(since C++20) |
Parameters
other | - | iterator adaptor to assign |
Return value
*this
Example
Run this code
#include <iostream> #include <iterator> int main() { const int a1[] {0, 1, 2}; int a2[] {0, 1, 2, 3}; short a3[] {40, 41, 42}; std::reverse_iterator<const int*> it1{ std::crbegin(a1) }; it1 = std::reverse_iterator<int*>{ std::rbegin(a2) }; // OK // it1 = std::reverse_iterator<short*>{ std::rbegin(a3) }; // compilation error: // incompatible pointer types std::reverse_iterator<short const*> it2{ nullptr }; it2 = std::rbegin(a3); // OK // it2 = std::begin(a3); // compilation error: no viable overloaded '=' std::cout << *it2 << '\n'; }
Output:
42
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3435 | C++20 | the converting assignment operator was not constrained | constrained |
See also
constructs a new iterator adaptor (public member function) |