std::bit_floor
From cppreference.com
Defined in header <bit>
|
||
template< class T > constexpr T bit_floor( T x ) noexcept; |
(since C++20) | |
If x
is not zero, calculates the largest integral power of two that is not greater than x
. If x
is zero, returns zero.
This overload participates in overload resolution only if T
is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
x | - | unsigned integer value |
Return value
Zero if x
is zero; otherwise, the largest integral power of two that is not greater than x
.
Notes
Feature-test macro: | __cpp_lib_int_pow2 |
Possible implementation
template <std::unsigned_integral T> requires !std::same_as<T, bool> && !std::same_as<T, char> && !std::same_as<T, char8_t> && !std::same_as<T, char16_t> && !std::same_as<T, char32_t> && !std::same_as<T, wchar_t> constexpr T bit_floor(T x) noexcept { if (x != 0) return T{1} << (std::bit_width(x) - 1); return 0; } |
Example
Run this code
#include <bit> #include <bitset> #include <iostream> int main() { using bin = std::bitset<8>; for (unsigned x = 0; x != 10; ++x) { auto const z = std::bit_floor(x); // `floor2` before P1956R1 std::cout << "bit_floor( " << bin(x) << " ) = " << bin(z) << '\n'; } }
Output:
bit_floor( 00000000 ) = 00000000 bit_floor( 00000001 ) = 00000001 bit_floor( 00000010 ) = 00000010 bit_floor( 00000011 ) = 00000010 bit_floor( 00000100 ) = 00000100 bit_floor( 00000101 ) = 00000100 bit_floor( 00000110 ) = 00000100 bit_floor( 00000111 ) = 00000100 bit_floor( 00001000 ) = 00001000 bit_floor( 00001001 ) = 00001000
See also
(C++20) |
finds the smallest integral power of two not less than the given value (function template) |
(C++20) |
computes the result of bitwise right-rotation (function template) |
(C++20) |
finds the smallest number of bits needed to represent the given value (function template) |
(C++20) |
checks if a number is an integral power of two (function template) |