std::countr_one
From cppreference.com
Defined in header <bit>
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template< class T > constexpr int countr_one( T x ) noexcept; |
(since C++20) | |
Returns the number of consecutive 1 bits in the value of x
, starting from the least significant bit ("right").
This overload participates in overload resolution only if T
is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
x | - | value of unsigned integer type |
Return value
The number of consecutive 1 bits in the value of x
, starting from the least significant bit.
Notes
Feature-test macro: | __cpp_lib_bitops |
Example
Run this code
#include <bit> #include <bitset> #include <cstdint> #include <iostream> int main() { for (const std::uint8_t i : { 0, 0b11111111, 0b11111110, 0b11100011 }) { std::cout << "countr_one( " << std::bitset<8>(i) << " ) = " << std::countr_one(i) << '\n'; } }
Output:
countr_one( 00000000 ) = 0 countr_one( 11111111 ) = 8 countr_one( 11111110 ) = 0 countr_one( 11100011 ) = 2
See also
(C++20) |
counts the number of consecutive 0 bits, starting from the most significant bit (function template) |
(C++20) |
counts the number of consecutive 1 bits, starting from the most significant bit (function template) |
(C++20) |
counts the number of consecutive 0 bits, starting from the least significant bit (function template) |
(C++20) |
counts the number of 1 bits in an unsigned integer (function template) |
(C++20) |
checks if a number is an integral power of two (function template) |
returns the number of bits set to true (public member function of std::bitset<N> ) | |
(C++11) |
checks if all, any or none of the bits are set to true (public member function of std::bitset<N> ) |