std::popcount
From cppreference.com
| Defined in header <bit>
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| template< class T > constexpr int popcount( T x ) noexcept; |
(since C++20) | |
Returns the number of 1 bits in the value of x.
This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
| x | - | value of unsigned integer type |
Return value
The number of 1 bits in the value of x.
Notes
| Feature-test macro: | __cpp_lib_bitops |
Example
Run this code
#include <bit> #include <bitset> #include <cstdint> #include <iostream> int main() { for (const std::uint8_t i : { 0, 0b11111111, 0b00011101 }) { std::cout << "popcount( " << std::bitset<8>(i) << " ) = " << std::popcount(i) << '\n'; } }
Output:
popcount( 00000000 ) = 0 popcount( 11111111 ) = 8 popcount( 00011101 ) = 4
See also
| (C++20) |
counts the number of consecutive 0 bits, starting from the most significant bit (function template) |
| (C++20) |
counts the number of consecutive 1 bits, starting from the most significant bit (function template) |
| (C++20) |
counts the number of consecutive 0 bits, starting from the least significant bit (function template) |
| (C++20) |
counts the number of consecutive 1 bits, starting from the least significant bit (function template) |
| (C++20) |
checks if a number is an integral power of two (function template) |
| returns the number of bits set to true (public member function of std::bitset<N>) | |
| (C++11) |
checks if all, any or none of the bits are set to true (public member function of std::bitset<N>) |