std::chrono::year_month_day_last::year, std::chrono::year_month_day_last::month, std::chrono::year_month_day_last::day, std::chrono::year_month_day_last::month_day_last
From cppreference.com
< cpp | chrono | year month day last
constexpr std::chrono::year year() const noexcept; |
(1) | (since C++20) |
constexpr std::chrono::month month() const noexcept; |
(2) | (since C++20) |
constexpr std::chrono::day day() const noexcept; |
(3) | (since C++20) |
constexpr std::chrono::month_day_last month_day_last() const noexcept; |
(4) | (since C++20) |
Retrieves the field values stored in this year_month_day_last
object.
Return values
1) Returns the stored std::chrono::year value.
2) Returns the stored std::chrono::month value.
3) A std::chrono::day value corresponding to the last day of the stored year and month. If this->ok() is false, the return value is unspecified.
4) A std::chrono::month_day_last constructed from
month()
.Example
Run this code
#include <iostream> #include <chrono> int main() { std::cout << std::boolalpha; constexpr auto ymdl {std::chrono::last/11/2020}; std::cout << (ymdl.day() == std::chrono::day(30)) << ' ' << (ymdl.month() == std::chrono::November) << ' ' << (ymdl.year() == std::chrono::year(2020)) << ' '; constexpr auto mdl = ymdl.month_day_last(); std::cout << (mdl == (std::chrono::November/std::chrono::last)) << '\n'; }
Output:
true true true true