std::chrono::year_month_day_last::ok
From cppreference.com
< cpp | chrono | year month day last
constexpr bool ok() const noexcept; |
(since C++20) | |
Checks if *this represents a valid date. Because a year_month_day_last
represents the last day of a particular month, it represents a valid date as long as the year and month are valid.
Return value
year().ok() && month().ok()
Example
Run this code
#include <iostream> #include <chrono> int main() { std::cout << std::boolalpha; auto ymdl {std::chrono::last/11/2020}; std::cout << (ymdl.ok()) << ' '; ymdl = std::chrono::year(2020)/std::chrono::month(13)/std::chrono::last; std::cout << (ymdl.ok()) << '\n'; }
Output:
true false