std::chrono::year_month_day_last::year_month_day_last
From cppreference.com
< cpp | chrono | year month day last
constexpr year_month_day_last( const std::chrono::year& y, const std::chrono::month_day_last& mdl ) noexcept; |
(since C++20) | |
Constructs a year_month_day_last
object storing the year y
and the month mdl.month(). The constructed object represents the last day of that year and month.
Notes
A year_month_day_last
can also be created by combining a std::chrono::year_month with std::chrono::last using operator/.
Example
Run this code
#include <chrono> #include <iostream> int main() { std::cout << "All last days of months of a given year: \n"; constexpr std::chrono::year year{2021}; for (int i{1}; i <= 12; ++i) { const std::chrono::month_day_last mdl{std::chrono::month(i) / std::chrono::last}; const std::chrono::year_month_day_last ymdl{year, mdl}; std::cout << ymdl << " day: " << ymdl.day() << '\n'; } }
Possible output:
All last days of months of a given year: 2021/Jan/last day: 31 2021/Feb/last day: 28 2021/Mar/last day: 31 2021/Apr/last day: 30 2021/May/last day: 31 2021/Jun/last day: 30 2021/Jul/last day: 31 2021/Aug/last day: 31 2021/Sep/last day: 30 2021/Oct/last day: 31 2021/Nov/last day: 30 2021/Dec/last day: 31
See also
(C++20) |
conventional syntax for Gregorian calendar date creation (function) |