Zero-initialization
Sets the initial value of an object to zero.
Syntax
Note that this is not the syntax for zero-initialization, which does not have a dedicated syntax in the language. These are examples of other types of initializations, which might perform zero-initialization.
static T object ;
|
(1) | ||||||||
T () ;
T t T |
(2) | ||||||||
CharT array [ n ] = " short-sequence ";
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(3) | ||||||||
Explanation
Zero-initialization is performed in the following situations:
The effects of zero-initialization are:
- If
T
is a scalar type, the object is initialized to the value obtained by explicitly converting the integer literal 0 (zero) toT
. - If
T
is an non-union class type:
- all padding bits are initialized to zero bits,
- each non-static data member is zero-initialized,
- each non-virtual base class subobject is zero-initialized, and
- if the object is not a base class subobject, each virtual base class subobject is zero-initialized.
- If
T
is a union type:
- all padding bits are initialized to zero bits, and
- the object’s first non-static named data member is zero-initialized.
- If
T
is array type, each element is zero-initialized. - If
T
is reference type, nothing is done.
Notes
As described in non-local initialization, static and thread-local (since C++11) variables that aren't constant-initialized are zero-initialized before any other initialization takes place. If the definition of a non-class non-local variable has no initializer, then default initialization does nothing, leaving the result of the earlier zero-initialization unmodified.
A zero-initialized pointer is the null pointer value of its type, even if the value of the null pointer is not integral zero.
Example
#include <string> #include <iostream> struct A { int a, b, c; }; double f[3]; // zero-initialized to three 0.0's int* p; // zero-initialized to null pointer value // (even if the value is not integral 0) std::string s; // zero-initialized to indeterminate value, then // default-initialized to "" by the std::string default constructor int main(int argc, char*[]) { delete p; // safe to delete a null pointer static int n = argc; // zero-initialized to 0 then copy-initialized to argc std::cout << "n = " << n << '\n'; A a = A(); // the effect is same as: A a{}; or A a = {}; std::cout << "a = {" << a.a << ' ' << a.b << ' ' << a.c << "}\n"; }
Possible output:
n = 1 a = {0 0 0}
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 277 | C++98 | pointers might be initialized with a non-constant expression of value 0, which is not a null pointer constant |
must initialize with an integral constant expression of value 0 |
CWG 694 | C++98 | zero-initialization for class types ignored padding | padding is initialized to zero bits |
CWG 903 | C++98 | zero-initialization for scalar types set the initial value to the value converted from an integral constant expression with value 0 |
the object is initialized to the value converted from the integer literal 0 |
CWG 2026 | C++98 | zero-initialization was specified to always occur first, even before constant initialization |
no zero-initialization if constant initialization applies |
CWG 2196 | C++98 | zero-initialization for class types ignored base class subobjects | they are also zero-initialized |
CWG 2253 | C++98 | it was unclear whether zero-initialization applies to unnamed bit-fields |
it applies (all padding bits are initialized to zero bits) |