std::variant<Types...>::emplace
From cppreference.com
(1) | ||
template <class T, class... Args> T& emplace(Args&&... args); |
(since C++17) (until C++20) |
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template <class T, class... Args> constexpr T& emplace(Args&&... args); |
(since C++20) | |
(2) | ||
template <class T, class U, class... Args> T& emplace( std::initializer_list<U> il, Args&&... args ); |
(since C++17) (until C++20) |
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template <class T, class U, class... Args> constexpr T& emplace( std::initializer_list<U> il, Args&&... args ); |
(since C++20) | |
(3) | ||
template <std::size_t I, class... Args> std::variant_alternative_t<I, variant>& emplace( Args&&... args ); |
(since C++17) (until C++20) |
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template <std::size_t I, class... Args> constexpr std::variant_alternative_t<I, variant>& emplace( Args&&... args ); |
(since C++20) | |
(4) | ||
template <std::size_t I, class U, class... Args> std::variant_alternative_t<I, variant>& |
(since C++17) (until C++20) |
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template <std::size_t I, class U, class... Args> constexpr std::variant_alternative_t<I, variant>& |
(since C++20) | |
Creates a new value in-place, in an existing variant
object
1) Equivalent to emplace<I>(std::forward<Args>(args)...), where
I
is the zero-based index of T
in Types...
.
- This overload participates in overload resolution only if std::is_constructible_v<T, Args...> is true, and
T
occurs exactly once inTypes...
2) Equivalent to emplace<I>(il, std::forward<Args>(args)...), where
I
is the zero-based index of T
in Types...
.
- This overload participates in overload resolution only if std::is_constructible_v<T, std::initializer_list<U>&, Args...> is true, and
T
occurs exactly once inTypes...
3) First, destroys the currently contained value (if any). Then direct-initializes the contained value as if constructing a value of type
T_I
with the arguments std::forward<Args>(args).... If an exception is thrown, *this may become valueless_by_exception.
- This overload participates in overload resolution only if std::is_constructible_v<T_I, Args...> is true.
- It is a compile-time error if
I
is not less than sizeof...(Types).
4) First, destroys the currently contained value (if any). Then direct-initializes the contained value as if constructing a value of type
T_I
with the arguments il, std::forward<Args>(args).... If an exception is thrown, *this may become valueless_by_exception.
- This overload participates in overload resolution only if std::is_constructible_v<T_I, std::initializer_list<U>&, Args...> is true.
- It is a compile-time error if
I
is not less than sizeof...(Types).
Parameters
args | - | constructor arguments to use when constructing the new value |
il | - | initializer_list argument to use when constructing the new value |
Return value
A reference to the new contained value.
Exceptions
1-4) Any exception thrown during the initialization of the contained value.
Example
Run this code
#include <iostream> #include <string> #include <variant> int main() { std::variant<std::string> v1; v1.emplace<0>("abc"); // OK std::cout << std::get<0>(v1) << '\n'; v1.emplace<std::string>("def"); // OK std::cout << std::get<0>(v1) << '\n'; std::variant<std::string, std::string> v2; v2.emplace<1>("ghi"); // OK std::cout << std::get<1>(v2) << '\n'; // v2.emplace<std::string>("abc"); -> Error }
Output:
abc def ghi
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
P2231R1 | C++20 | emplace was not constexpr while the required operations can be constexpr in C++20
|
made constexpr |
See also
assigns a variant (public member function) |