std::hash <std::variant>
From cppreference.com
Defined in header <variant>
|
||
template <class... Types> struct hash<std::variant<Types...>>; |
(since C++17) | |
The template specialization of std::hash for the std::variant template allows users to obtain hashes of variant
objects.
The specialization std::hash<std::variant<Types...>> is enabled (see std::hash) if every specialization in std::hash<std::remove_const_t<Types>>... is enabled, and is disabled otherwise.
The member functions of this specialization are not guaranteed to be noexcept.
Template parameters
Types | - | the types of the alternatives supported by the variant object
|
Notes
Unlike std::hash<std::optional>, hash of a variant does not typically equal the hash of the contained value; this makes it possible to distinguish std::variant<int, int> holding the same value as different alternatives.
Example
Run this code
#include <variant> #include <iostream> #include <string> using Var = std::variant<int, int, int, std::string>; template<unsigned I> void print(Var const& var) { std::cout << "get<" << var.index() << "> = " << std::get<I>(var) << "\t" "# = " << std::hash<Var>{}(var) << '\n'; } int main() { Var var; std::get<0>(var) = 2020; print<0>(var); var.emplace<1>(2023); print<1>(var); var.emplace<2>(2026); print<2>(var); var = "C++"; print<3>(var); }
Possible output:
get<0> = 2020 # = 2020 get<1> = 2023 # = 2024 get<2> = 2026 # = 2028 get<3> = C++ # = 15518724754199266859
See also
(C++11) |
hash function object (class template) |