std::variant<Types...>::operator=
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                    |   constexpr variant& operator=( const variant& rhs );  | 
(1) | (since C++17) | 
|   constexpr variant& operator=( variant&& rhs ) noexcept(/* see below */);  | 
(2) | (since C++17) | 
| (3) | ||
|   template< class T >  variant& operator=( T&& t ) noexcept(/* see below */);  | 
 (since C++17)  (until C++20)  | 
|
|   template< class T >  constexpr variant& operator=( T&& t ) noexcept(/* see below */);  | 
(since C++20) | |
Assigns a new value to an existing variant object.
1) Copy-assignment:
-  If both *this and 
rhsare valueless by exception, does nothing. -  Otherwise, if 
rhsis valueless, but *this is not, destroys the value contained in *this and makes it valueless. -  Otherwise, if 
rhsholds the same alternative as *this, assigns the value contained inrhsto the value contained in *this. If an exception is thrown, *this does not become valueless: the value depends on the exception safety guarantee of the alternative's copy assignment. -  Otherwise, if the alternative held by 
rhsis either nothrow copy constructible or not nothrow move constructible (as determined by std::is_nothrow_copy_constructible and std::is_nothrow_move_constructible, respectively), equivalent to this->emplace<rhs.index()>(get<rhs.index()>(rhs)). *this may becomevalueless_by_exceptionif an exception is thrown on the copy-construction insideemplace. - Otherwise, equivalent to this->operator=(variant(rhs)).
 
 This overload is defined as deleted unless std::is_copy_constructible_v<T_i> and std::is_copy_assignable_v<T_i> are both true for all 
T_i in Types.... This overload is trivial if std::is_trivially_copy_constructible_v<T_i>,std::is_trivially_copy_assignable_v<T_i> and std::is_trivially_destructible_v<T_i> are all true for all T_i in Types....2) Move-assignment:
-  If both *this and 
rhsare valueless by exception, does nothing -  Otherwise, if 
rhsis valueless, but *this is not, destroys the value contained in *this and makes it valueless -  Otherwise, if 
rhsholds the same alternative as *this, assigns std::get<j>(std::move(rhs)) to the value contained in *this, withjbeingindex(). If an exception is thrown, *this does not become valueless: the value depends on the exception safety guarantee of the alternative's move assignment. -  Otherwise (if 
rhsand*thishold different alternatives), equivalent to this->emplace<rhs.index()>(get<rhs.index()>(std::move(rhs))). If an exception is thrown byT_i's move constructor, *this becomesvalueless_by_exception. 
 This overload participates in overload resolution only if std::is_move_constructible_v<T_i> and std::is_move_assignable_v<T_i> are both true for all 
T_i in Types.... This overload is trivial if std::is_trivially_move_constructible_v<T_i>, std::is_trivially_move_assignable_v<T_i>, and std::is_trivially_destructible_v<T_i> are all true for all T_i in Types....3) Converting assignment. 
-  Determines the alternative type 
T_jthat would be selected by overload resolution for the expression F(std::forward<T>(t)) if there was an overload of imaginary function F(T_i) for everyT_ifromTypes...in scope at the same time, except that: 
-  An overload F(T_i) is only considered if the declaration T_i x[] = { std::forward<T>(t) }; is valid for some invented variable 
x; 
-  An overload F(T_i) is only considered if the declaration T_i x[] = { std::forward<T>(t) }; is valid for some invented variable 
 
-  If *this already holds a 
T_j, assigns std::forward<T>(t) to the value contained in *this. If an exception is thrown, *this does not become valueless: the value depends on the exception safety guarantee of the assignment called. -  Otherwise, if std::is_nothrow_constructible_v<T_j, T> || !std::is_nothrow_move_constructible_v<T_j> is true, equivalent to this->emplace<j>(std::forward<T>(t)). *this may become 
valueless_by_exceptionif an exception is thrown on the initialization insideemplace. - Otherwise, equivalent to this->emplace<j>(T_j(std::forward<T>(t))).
 
This overload participates in overload resolution only if std::decay_t<T> (until C++20)std::remove_cvref_t<T> (since C++20) is not the same type as variant and std::is_assignable_v<T_j&, T> is true and std::is_constructible_v<T_j, T> is true and the expression F(std::forward<T>(t)) (with F being the above-mentioned set of imaginary functions) is well formed.
std::variant<std::string> v1; v1 = "abc"; // OK std::variant<std::string, std::string> v2; v2 = "abc"; // Error std::variant <std::string, bool> v3; v3 = "abc"; // OK, chooses string; bool is not a candidate std::variant<float, long, double> v4; //holds float v4 = 0; // OK, holds long; float and double are not candidates
Parameters
| rhs | - |   another variant
 | 
| t | - | a value convertible to one of the variant's alternatives | 
Return value
*this
Exceptions
1) May throw any exception thrown by assignment and copy/move initialization of any alternative.
2) 
noexcept specification:  
noexcept(((std::is_nothrow_move_constructible_v<Types> &&
std::is_nothrow_move_assignable_v<Types>) && ...))
std::is_nothrow_move_assignable_v<Types>) && ...))
3) 
noexcept specification:  
noexcept(std::is_nothrow_assignable_v<T_j&, T> && std::is_nothrow_constructible_v<T_j, T>)
Example
Run this code
#include <iomanip> #include <iostream> #include <string> #include <type_traits> #include <variant> std::ostream& operator<<(std::ostream& os, std::variant<int, std::string> const& va) { os << ": { "; std::visit([&](auto&& arg) { using T = std::decay_t<decltype(arg)>; if constexpr (std::is_same_v<T, int>) os << arg; else if constexpr (std::is_same_v<T, std::string>) os << std::quoted(arg); }, va); return os << " };\n"; } int main() { std::variant<int, std::string> a{2017}, b{"CppCon"}; std::cout << "a" << a << "b" << b << '\n'; std::cout << "(1) operator=( const variant& rhs )\n"; a = b; std::cout << "a" << a << "b" << b << '\n'; std::cout << "(2) operator=( variant&& rhs )\n"; a = std::move(b); std::cout << "a" << a << "b" << b << '\n'; std::cout << "(3) operator=( T&& t ), where T is int\n"; a = 2019; std::cout << "a" << a << '\n'; std::cout << "(3) operator=( T&& t ), where T is std::string\n"; std::string s{"CppNow"}; std::cout << "s: " << std::quoted(s) << '\n'; a = std::move(s); std::cout << "a" << a << "s: " << std::quoted(s) << '\n'; }
Possible output:
a: { 2017 };
b: { "CppCon" };
 
(1) operator=( const variant& rhs )
a: { "CppCon" };
b: { "CppCon" };
 
(2) operator=( variant&& rhs )
a: { "CppCon" };
b: { "" };
 
(3) operator=( T&& t ), where T is int
a: { 2019 };
 
(3) operator=( T&& t ), where T is std::string
s: "CppNow"
a: { "CppNow" };
s: ""Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior | 
|---|---|---|---|
| LWG 3024 | C++17 |  copy assignment operator doesn't participate in overload resolution if any member type is not copyable  | 
defined as deleted instead | 
| P0602R4 | C++17 |  copy/move assignment may not be trivial even if underlying operations are trivial  | 
required to propagate triviality | 
| P0608R3 | C++17 |  converting assignment blindly assembles an overload set, leading to unintended conversions  | 
 narrowing and boolean conversions not considered  | 
| P2231R1 | C++20 |  converting assignment was not constexpr while the required operations can be in C++20  | 
made constexpr | 
| LWG 3585 | C++17 |  converting assignment was sometimes unexpectedly ill-formed because there was no available move assignment  | 
made well-formed | 
See also
|    constructs a value in the variant, in place  (public member function)  |