std::is_corresponding_member
From cppreference.com
Defined in header <type_traits>
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template<class S1, class S2, class M1, class M2> constexpr bool is_corresponding_member( M1 S1::* mp, M2 S2::* mq ) noexcept; |
(since C++20) | |
Determines whether mp
and mq
refer corresponding members in the common initial sequence of S1
and S2
. The program is ill-formed if either S1
or S2
is an incomplete type.
If either S1
or S2
is not a StandardLayoutType, or either M1
or M2
is not an object type, or either mp
or mq
is equal to nullptr, the result is always false.
Parameters
mp, mq | - | pointers-to-member to detect |
Return value
true if mp
and mq
refer corresponding members in the common initial sequence of S1
and S2
, otherwise false.
Notes
The type of a pointer-to-member expression &S::m is not always M S::*, where m
is of type M
, because m
may be a member inherited from a base class of S
. The template arguments can be specified in order to avoid potentially surprising results.
Example
Run this code
#include <type_traits> #include <iostream> struct Foo { int x; }; struct Bar { int y; double z; }; struct Baz : Foo, Bar {}; // not standard-layout int main() { std::cout << std::boolalpha << std::is_same_v<decltype(&Baz::x), int Foo::*> << '\n' << std::is_same_v<decltype(&Baz::y), int Bar::*> << '\n' << std::is_corresponding_member(&Foo::x, &Bar::y) << '\n' << std::is_corresponding_member(&Baz::x, &Baz::y) << '\n' << std::is_corresponding_member<Baz, Baz, int, int>(&Baz::x, &Baz::y) << '\n'; }
Output:
true true true true false
See also
(C++11) |
checks if a type is a standard-layout type (class template) |
(C++20) |
checks if two types are layout-compatible (class template) |
(C++11) |
checks if a type is a pointer to a non-static member object (class template) |