std::remove_pointer
From cppreference.com
Defined in header <type_traits>
|
||
template< class T > struct remove_pointer; |
(since C++11) | |
Provides the member typedef type
which is the type pointed to by T
, or, if T
is not a pointer, then type
is the same as T
.
The behavior of a program that adds specializations for remove_pointer
is undefined.
Member types
Name | Definition |
type
|
the type pointed to by T or T if it's not a pointer
|
Helper types
template< class T > using remove_pointer_t = typename remove_pointer<T>::type; |
(since C++14) | |
Possible implementation
template< class T > struct remove_pointer {typedef T type;}; template< class T > struct remove_pointer<T*> {typedef T type;}; template< class T > struct remove_pointer<T* const> {typedef T type;}; template< class T > struct remove_pointer<T* volatile> {typedef T type;}; template< class T > struct remove_pointer<T* const volatile> {typedef T type;}; |
Example
Run this code
#include <iostream> #include <type_traits> template<class T1, class T2> void print_is_same() { std::cout << std::is_same<T1, T2>() << '\n'; } void print_separator() { std::cout << "-----\n"; } int main() { std::cout << std::boolalpha; print_is_same<int, int>(); // true print_is_same<int, int*>(); // false print_is_same<int, int**>(); // false print_separator(); print_is_same<int, std::remove_pointer<int>::type>(); // true print_is_same<int, std::remove_pointer<int*>::type>(); // true print_is_same<int, std::remove_pointer<int**>::type>(); // false print_separator(); print_is_same<int, std::remove_pointer<int* const>::type>(); // true print_is_same<int, std::remove_pointer<int* volatile>::type>(); // true print_is_same<int, std::remove_pointer<int* const volatile>::type>(); // true }
Output:
true false false ----- true true false ----- true true true
See also
(C++11) |
checks if a type is a pointer type (class template) |
(C++11) |
adds a pointer to the given type (class template) |