std::is_scoped_enum
Defined in header <type_traits>
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template< class T > struct is_scoped_enum; |
(since C++23) | |
Checks whether T
is a scoped enumeration type. Provides the member constant value
which is equal to true, if T
is a scoped enumeration type. Otherwise, value
is equal to false.
The behavior of a program that adds specializations for is_scoped_enum
or is_scoped_enum_v
is undefined.
Template parameters
T | - | a type to check |
Helper variable template
template< class T > inline constexpr bool is_scoped_enum_v = is_scoped_enum<T>::value; |
(since C++23) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is a scoped enumeration type , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
Notes
As currently the standard allows the name of an enumeration type appears in its enum-base, for example, enum class E : std::enable_if_t<std::is_scoped_enum_v<E>, int> {}; is allowed, std::is_scoped_enum
cannot be implemented without extensions, because scoped and unscoped enumeration types are indistinguishable in expressions when they are incomplete.
However, all known compilers consider an enumeration type is still undeclared in its enum-base. As a result, a scoped enumeration type can never be incomplete, and std::is_scoped_enum
can be implemented like below. This is CWG issue 2516.
Feature-test macro: | __cpp_lib_is_scoped_enum |
Possible implementation
This implementation assumes that scoped enumeration types are always complete.
namespace detail { namespace { // avoid ODR-violation template<class T> auto test_sizable(int) -> decltype(sizeof(T), std::true_type{}); template<class> auto test_sizable(...) -> std::false_type; template<class T> auto test_nonconvertible_to_int(int) -> decltype(static_cast<std::false_type (*)(int)>(nullptr)(std::declval<T>())); template<class> auto test_nonconvertible_to_int(...) -> std::true_type; template<class T> constexpr bool is_scoped_enum_impl = std::conjunction_v< decltype(test_sizable<T>(0)), decltype(test_nonconvertible_to_int<T>(0)) >; } } // namespace detail template<class> struct is_scoped_enum : std::false_type {}; template<class E> requires std::is_enum_v<E> struct is_scoped_enum<E> : std::bool_constant<detail::is_scoped_enum_impl<E>> {}; |
Example
#include <iostream> #include <type_traits> class A {}; enum E {}; enum struct Es { oz }; enum class Ec : int {}; int main() { std::cout << std::boolalpha; std::cout << std::is_scoped_enum_v<A> << '\n'; std::cout << std::is_scoped_enum_v<E> << '\n'; std::cout << std::is_scoped_enum_v<Es> << '\n'; std::cout << std::is_scoped_enum_v<Ec> << '\n'; std::cout << std::is_scoped_enum_v<int> << '\n'; }
Output:
false false true true false
See also
(C++11) |
checks if a type is an integral type (class template) |
(C++11) |
checks if a type is an arithmetic type (class template) |
(C++11) |
checks if a type is a scalar type (class template) |
(C++11) |
checks if a type is an enumeration type (class template) |