std::ranges::ssize
Defined in header <ranges>
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inline namespace /*unspecified*/ { inline constexpr /*unspecified*/ ssize = /*unspecified*/; |
(since C++20) (customization point object) |
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Call signature |
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template< class T > requires /* see below */ |
(since C++20) | |
Returns the size of a range converted to a signed type.
If ranges::size(std::forward<T>(t)) is well-formed, a call to ranges::ssize
is expression-equivalent to static_cast<MadeSigned>(ranges::size(std::forward<T>(t))), where MadeSigned
denotes
- the corresponding signed version of decltype(ranges::size(std::forward<T>(t))), if it is wider than std::ptrdiff_t, or
- std::ptrdiff_t otherwise.
If ranges::size(std::forward<T>(t)) is ill-formed, a call to ranges::ssize
is also ill-formed, which can result in substitution failure when ranges::ssize(t) appears in the immediate context of a template instantiation.
Expression-equivalent
Expression e is expression-equivalent to expression f, if
- e and f have the same effects, and
- either both are constant subexpressions or else neither is a constant subexpression, and
- either both are potentially-throwing or else neither is potentially-throwing (i.e. noexcept(e) == noexcept(f)).
Customization point objects
The name ranges::ssize
denotes a customization point object, which is a const function object of a literal semiregular
class type. For exposition purposes, the cv-unqualified version of its type is denoted as __ssize_fn
.
All instances of __ssize_fn
are equal. The effects of invoking different instances of type __ssize_fn
on the same arguments are equivalent, regardless of whether the expression denoting the instance is an lvalue or rvalue, and is const-qualified or not (however, a volatile-qualified instance is not required to be invocable). Thus, ranges::ssize
can be copied freely and its copies can be used interchangeably.
Given a set of types Args...
, if std::declval<Args>()... meet the requirements for arguments to ranges::ssize
above, __ssize_fn
models
- std::invocable<__ssize_fn, Args...>,
- std::invocable<const __ssize_fn, Args...>,
- std::invocable<__ssize_fn&, Args...>, and
- std::invocable<const __ssize_fn&, Args...>.
Otherwise, no function call operator of __ssize_fn
participates in overload resolution.
Notes
If ranges::ssize(e) is valid for an expression e, the return type is a signed-integer-like type, i.e. an integer type for which std::is_signed_v is true, or a signed-integer-class type.
The width of integer-like types can be detected by std::numeric_limits::digits.
Example
#include <array> #include <iostream> #include <ranges> #include <type_traits> int main() { std::array arr{1, 2, 3, 4, 5}; auto s = std::ranges::ssize(arr); std::cout << "ranges::ssize(arr) = " << s << '\n' << "ranges::ssize is " << (std::is_signed_v<decltype(s)> ? "signed" : "unsigned") << '\n'; std::cout << "reversed arr: "; for (--s; s >= 0; --s) std::cout << arr[s] << ' '; std::cout << "\n" "s = " << s << '\n'; }
Output:
ranges::ssize(arr) = 5 ranges::ssize is signed reversed arr: 5 4 3 2 1 s = -1
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
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LWG 3403 | C++20 | ranges::size worked for some non-range types but ranges::ssize didn't
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made work |
See also
(C++20) |
returns an integer equal to the size of a range (customization point object) |
(C++20) |
specifies that a range knows its size in constant time (concept) |
(C++17)(C++20) |
returns the size of a container or array (function template) |